17.04.2009, 07:02 PM
Zitat:The part should not be used as a comparator, peak detector or other open-loop application with large, sustained differential inputs Under normal, closed-loop operation, an increase of power dis- sipation is only noticeable in applications with large slewing outputs and is proportional to the magnitude of the differential input voltage and the percent of the time that the inputs are apart. Measure the average supply current for the application in order to calculate the power dissipa- tion.
Nee...er will die Differenz ausgleichen und macht intern alles an was er hat ... das brint ihn um, nicht der Eingangstrom, die anliegende Spannung ... Currentfeedback ...
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